m= 29 if m%3!=0: print (m, "不能被3整除") else print (m,“能被3整除") |
①由像素组成;②放大后出现失真;③可以被任意放大,清晰度不会改变;④存储空间较小。
x=int(input("请输入第1个数:"))
y=int(input("请输入第2个数:"))
if x>y:
print(x)
else:
print(y)
图a
每本书对应一个唯一的书名编码,请回答下列问题:
(提示:SUMIF函数用于对区域中满足条件的单元格求和,例如:=SUMIF(B3:B9,B3,E3:E9),表示区域B3:B9中“书名”是“《量子力学》”的所有“小计”的和)
图b
s = Text1.Text
ch = Mid(s,1,1):Max= 0
For i=2 To Len(s)
If Mid(s,i,1)>= Mid(s,i-1,1) Then
ch=ch+Mid(s,i,1)
If Len(ch)> Max Then Max = Len(ch): ans = ch
Else
ch = Mid(s,i,1)
End If
Next i
在文本框Text1中输入“Access2010*”。执行该程序段后,变量ans的值为( )
Const n = 11
Dim key As Integer, L As Integer, R As Integer, m As Integer
key = Val(Text1. Text)
For i = n To 2 Step-1
L = 1
R = ①
Do While L < = R
m = (L+R) \ 2
If c(i) + c(m) = key Then
Label2 Caption = c(1) & “ “& c(m)
Exit For
ElseIf Then ‘②
L = m+1
Else
R = m-1
End If
Loop
Next 1
If L > R Then Label2. Caption = “没有找到数对”
① ②
下列选择正确的是( )