下列说法不正确的是( )
For i=1 To 3
For j=i To 5
If a(j) > a(j+1) Then
t=a(j): a(j)=a(j+1): a(j+1)=t
End If
Next j
List1.AdcIItem Str(a(i))
Next i
a(1)到a(6)的初始值依次为“8 6 5 7 9 3 ”,经过该程序段“加工”后,列表框List1中显示的是( )
s = "20210606"
c1 = 6
n = 0
For i = 1 To Len(s)
c = Val(Mid(s, i, 1))
If c < c1 Then
n = n + 1: c1 = c
Next i
运行该程序段后,n 的值为( )
图1
图2
图3