题目
计算:(第(1)(2)题每题3分,第(3)题5分,共11分)
(1)
-20200+ +22
(2)
(6a2b²-9a²)÷(-3a)2
(3)
化简求值:[(y-2x)(-2x-y)-4(x-2y)2]
÷2y,其中x=1,y=-2
答案: 原式=12-1+(-3)+4=12
原式=(6a2b2-9a2)÷(9a2) =6a2b2÷9a2-9a2÷9a2 =23b2-1
原式=[-(y-2x)(y+2x)-4(x2-4xy+4y2)]÷2y =[-(y2-4x2)-4x2+16xy-16y2]÷2y =[-y2+4x2-4x2+16xy-16y2]÷2y =(16xy-17y2)÷2y =8x-172y ∵x=1,y=-2 ∴8x-172y=8+17=25