题目

设f(z)=,z1=3+4i,z2=-2-i,则f(z1-z2)是（    ）A.1-3i              B.-2+11i             C.-2+i             D.5-5i 答案：解析：z1-z2=(3+4i)-(-2-i)=5+5i.∴f(z1-z2)=f(5+5i)==5-5i.答案：D

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