题目

设集合A={x|x2-x-6＞0},B={x|(x-k)(x-k-1)＜0},若A∩B≠,则k的取值范围是(    )A.{k|k＜-3或k＞1}                       B.{k|-2＜k＜2}C.{k|k＜-2或k＞2}                       D.{k|-3≤k≤1} 答案：C解析:A={x|x＞3或x＜-2},B={x|k＜x＜k+1},∵A∩B≠,∴k＜-2或k+1＞3.∴k＜-2或k＞2.

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