题目

数列{an}满足an+an+1=10,a1=2,n∈N*,那么数列{an}不同的项共有A.1个                                                             B.2个C.3个                                                             D.无穷多个 答案：解析:a1+a2=10,∴a2=8.又a2+a3=10,∴a3=2.又a3+a4=10,∴a4=8.…猜想a2n－1=2,a2n=8.答案:B

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