题目

算式2(3+1)(32+1)(34+1)(38+1)(316+1)(332+1)+1计算的结果个位是几？ 答案：解：2(3+1)(32+1)(34+1)(38+1)(316+1)(332+1)+1 =(3−1)(3+1)(32+1)(34+1)(38+1)(316+1)(332+1)+1 =(32−1)(32+1)(34+1)(38+1)(316+1)(332+1)+1 =(34−1)(34+1)(38+1)(316+1)(332+1)+1 ⋯⋯  =364−1+1 =364  ， ∵3=3，3=9，3=27，3=81，35=243 ， ∴个位数每4个数一循环， ∵64÷4=16 ， ∴364 的个位数为1， 即结果个位是1．

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