题目
(本小题满分9分)已知⊙与⊙相交于、两点,点在⊙上,为⊙上一点(不与,,重合),直线与⊙交于另一点。(1)如图(8),若是⊙的直径,求证:;(2)如图(9),若是⊙外一点,求证:;(3)如图(10),若是⊙内一点,判断(2)中的结论是否成立。
答案:证明:(1)如图(一),连接,∵为⊙的直径 ∴∴为⊙的直径 ∴在上又,为的中点∴△是以为底边的等腰三角形∴····················································································· (3分)(2)如图(二),连接,并延长交⊙与点,连∵四边形内接于⊙ ∴又∵ ∴∴又为⊙的直径 ∴∴···················································································· (3分)(3)如图(三),连接,并延长交⊙与点,连∵ 又∴ ∴ 又∴···················································································· (3分)解析:略