a(1)=1:a(2)=1
B(1)=1:b(2)=2
For i=3 to 5
a(i)=a(i-1)+a(i-2)
b(i)=b(i-1)+a(i)
Next i
执行该程序后,数组元素b(5)的值为( )
x=0
For i=1 to 10 step
If then x=x+i
Next i
s='t1Hr2a3'
s1='' ; s2=''; i = 0
while i < len(s):
if '0'<=s[i]<='9':
s1 = s1 + s[i]
elif 'a'<=s[i]<='z':
s2 = s[i] + s2
i = i + 1
ans = s2 + s1
print(ans)
程序执行后,输出的结果是( )