
。

实现上述功能的 VB 程序代码如下,请回答下列问题。
Private Sub Command1_Click() Dim a, b, c, d, z As Integer d = 0
For a = 1 To 3 'a代表百位
For b = 0 To 3 'b代表十位
For c = 0 To 3
If a <> b And b <> c And c <> a Then ① list1.AddItem str(z) d = d + 1
End If
Next c
Next b Next a
label1.Caption = "共有" + ② + "个数"
End Sub
划线①处应填入的代码为 ;划线②处应填入的代码为
算法分析:从A点到B点共有7个路口,即可以有一个7位二进制数表示所走路线。观察以上路线,枚举所有满足路线特征的7位二进制数,再去掉不满足的二进制数即可。
Private Sub Command1_Click()
Dim b As String, t As Integer, i As Integer, c As Integer, d As Integer
t = 0 '可走路线计数
For i = 15 To 120 '所有可走路线用十进制枚举
d = i
c = 0
b = ""
Do While d <> 0
If d Mod 2 = 1 Then
b = "1" + b
c = c + 1
If c > 4 Then Exit Do '若"1"的总数超过 4 个表示路线错误,需退出 Do 循环
Else
①
End If
②
Loop
If c = 4 And Len(b) = 7 Then
t = t + 1
List1.AddItem b
End If
Next i
Label1.Caption = Str(t) + " 条"
End Sub
① ②
Dim a (1 To 4020 ) As String
Dim b (1 To 2000 ) As String
Private Sub Form_Load( )
Dim conn As New ADODB.Connection
Dim rs As New ADODB.Recordset
Dim constr As string
constr=“Provider=Microsoft.ace.OLEDB.12.0;”
constr=constr &“Data Source=” & App.Path+“\data\KaoSheng.accdb”
conn.ConnectionString=constr
conn.open()
Dim sql As String
‘将参加2010年下半年考试的考生的身份证号码按升序存放在a数组中
sql=“select * from kaoshengInfo where year=‘2010’order by sfzh asc”
rs.Open sql,conn
i=0
Do While Not rs.EOF
i=i+1
a(i)=rs(“sfzh”)
List1.additem(a(i))
rs.MoveNext
Loop
‘将参加2011年下半年考试的考生的身份证号码按升序存放在b数组中
sql=“select * from kaoshengInfo where year=‘2011’order by sfzh asc”
rs.Open sql,conn
i=0
Do While Not rs.EOF
i=i+1
b(i)=rs(“sfzh”)
List2.additem(b(i))
rs.MoveNext
Loop
rs.Close
End Sub
Private Sub Command1_Click ()
Dim bot As Integer, top As Integer, m As Integer
Dim i As Integer, ans As Integer
ans=0
For i=1 To 2000
bot=1
Do While bot <=top
m=Fix ( ( bot+top ) / 2 )
If a ( m )=b ( i ) Then
List3.AddItem a ( m )
Exit Do
ElseIf Then
top=m-1
Else
bot=m+1
End If
Loop
Next i
List3.AddItem“总计”+str(ans)+“人次”
End Sub
最佳方案:初始时所有人聚集在2号房间,花费的能量和:7*0+8*1+6*2+4*3+4*4=48。为了解决这个问题,小明编写了一个VB程序。在窗体加载时,从数据库中读取N的值和编号为1到N的房间的居住人数,人数存储在数组a中。点击窗体上的按钮Command1,程序枚举每一种方案(不同的初始房间),计算该方案的能量和,在文本框Text1中输出最优方案的初始房间编号,在文本框Text2中输出最小能量和。
实现上述功能的VB代码如下,请在划线处填入合适代码。
Dim a(1 To 100) As Integer ’依次存储编号为1到100的房间的居住人数
Private Sub Form_Load()
‘本过程从数据库中读取N的值和每个房间居住人数,存储在数组a中
‘代码略
End Sub
Private Sub Command1_Click()
Dim i As Integer, j As Integer, w As Integer, k as Integer
Dim t As Long, ans As Long
k=0 : ans = 32767 ‘ans初始化为最大的Integer数据
For i = 1 To n
t = 0
For j = 0 To n - 1
w=
If w = 0 Then w = n
t=
Next j
If t < ans Then
k= i
ans = t
End If
Next i
Text1.Text = Str (k) ‘起始房间编号
Text2.Text =
End Sub
①不大于n(n的值是由键盘输入);
②能被9整除;
③十位数是2。
算法流程图如图所示:
Dim n as Integer, x as Integer, s as long
s=0
n=InputBox(“输入四位数上限值”)
For ⑴
If ⑵ and ⑶ Then
S=s+x
End If
Next
⑷
⑴ ⑵ ⑶ ⑷
Private Sub Command1_Click()
i=1
j=7
Do While _______
i=_______
j=________
Loop
Text1.Text=Str(i)
Text2.Text=Str(j)
End Sub
则下列说法正确的是( )
①密码是六位数字,前面两位为59;
②最后两位数字相同;
③能被12和38整除。
程序界面如图所示,单击“找回密码”按钮(Command1)后,可能的密码显示在列表框List1中。
Private Sub Command1_Click( )
Dim x As Integer, s As Long, y As Integer, i As Integer
For i=0 To 9999
s=590000+i
If ① Then
x=s mod 10
y=(s Mod 100)\10
If ② Then
List1.AddItem ③
End If
End If
Next i
End Sub
①,②,③
A.x=y B.Str(s) C.Str(i) D.s Mod 12=0 and s Mod 38=0
Private Sub Command1_Click()
Dim i As Integer, n As Integer
Dim s As Integer, t As Integer, k As Integer
s = 0
For i = 1 To 1000
n = i
t = 0
k = 0
Do While n > 0
If n Mod 2 = 1 Then t = t + 1 Else k = k + 1
Loop
If Then s = s + 1
Next i
Text1.Text = Str(s)
End Sub
Private Sub Command1_Click()
Dim i As Integer, n As Integer
Dim s As Integer 's为A类数的个数
Dim t As Integer 't为二进制数中“1”的个数
Dim k As Integer 'k为二进制数中“0”的个数
s=0
For i=1 To 1000
n=i: t=0: k=0
Do While n>0
If Then t=t+1 Else k=k+1
Loop
If t>k Then
List1.Additem Str(i)
s=s+1
End If
Next i
Text1.Text=Str(s)
End Sub

h=
s=input('触地前的发光颜色变化:')
d={'R':0.8,'G':0.6,'B':0.5}
sum=h
for i in range(1,len(s)):
h=d[c]*h
sum=
print('弹球发光状态下的运动轨迹长度:'+str(sum))
def f(x):#求真因子和
s=0
for i in range(1, x//2+1) :
if ① :
s=s+i
return S
c=0
for i in range(1, 1001) :
if ② :
c=c+1
print (c)
① ②
, 其中n为正整数,计算s值的VB程序段如下:
s=1:i=1:t=1
Do While i<2*n-1
![]()
Loop
方框中的代码由以下三部分组成:
①s=s+t
②i=i+2
③t= -t/(i*(i- 1))
下列选项中,代码顺序正确的是( )