题目

数列{－2n2+29n+3}中的最大项是A.108                                                              B.107C.106                                                              D.109 答案：解析:∵二次函数y=－2x2+29x+3,当x=－=7时,y有最大值,但n∈N*,而与7最近的整数为7.故当n=7时,a7=108是数列的最大项.答案:A

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