题目

已知f(x)=x(x-1)(x-2)(x-3)(x-4)(x-5),则f′(0)为(    )A.-5                B.-5!                C.0                  D.-1 答案：解析:f′(x)=(x-1)(x-2)(x-3)(x-4)(x-5)-x［(x-1)(x-2)(x-3)(x-4)(x-5)］′,    ∴f′(0)=-1×(-2)×(-3)×(-4)×(-5)=-5!.答案:B

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