解决此问题可采用自底至顶分析的方法。如图a所示的数塔中,先从第3层开始分析:如果路径经过第3层的第1个数字12,那么从12到尾结点的路径上数字之和的最大值是当前结点值加上该结点左下方、右下方结点中的较大值,记作f(3,1)=12+141同理,f(3,2)=7+15、f(3,3)=26+15:再分析第2层,计算f(2,1)、f(2,2):最后计算出第1层f(1,1),即为所求结果。

Const n= 5
Dim a(1 To n^2) As Integer ‘数组a存储数塔数据,存储结构如图c所示
Dim f(1 To n^2) As Integer ‘数组f存储从第i层第j个数到底层尾结点的最大数字之和,其存储结构与数组a一样
Private Sub Command2Click()
‘生成数塔,将数据存入a数组中,代码略
End Sub
Private Sub Command2Click()
Dim i As Integer, j As Integer, k As Integer
For j=1 To n
f((n-1)*n+j)=
Next j
For i=
For j=1 To i
k=(1-1)*n+j
f(k)=
Next j
Next i
Label1.Caption=“路径上的数字和最大值为:"+Str(f(1)
End Sub
Function max(a As Integer, b As Integer) As Integer
If a>b Then max=a Else max=b
End Function
while True:
for event in pygame.event.get(): #()
if event.type==pygame.QUIT: #( )
sys.exit() #退出程序
if event.type==pygame.MOUSEBUTTONDOWN: #( )
from ① #导入tkinter模块
import tkinter.messagebox #导入弹窗库模块
import random #导入随机数模块
import datetime #导入日期时间模块
root = Tk() #创建主窗口
root.title("随机点名器") #设置窗口标题
root.geometry('808x280+300+200') #设置窗口大小及位置
root.resizable(0,0) #禁止调整窗口大小
var=StringVar() #定义StringVar()类型
var1=StringVar()
c=②("点名册.txt",'r') #以只读模式打开文件
a=c.readlines() #读取文件全部内容
c. ③ #关闭文件
b=[] #b作为列表a的备份
Private Sub Command1_Click( )
Dim a As Integer, b As Integer, c As Integer
A=Val(Text1.Text): b=Val(Text2.Text): c=Val(Text3.Text)
Label2.Caption=Str(fx(a, b, c))
End Sub
Function fx(x As Integer, y As Integer, z As Integer) As Integer
If x<y Then fx=z
If x>y Then fx=y Else fx=x
End Function
Dim C As Long
A="456":B="123": C=Val(A+B)
该程序段运行后,C的值为
def chanageInt (number2) :
number2 = number2+1
print ("changeInt: number2=", number2)
#调用
Number1 = 2
chanageInt (number1)
print ("number:", number1)
打印结果哪项是正确的( )。
For i=1 To 5
a(i)=Int (Rnd*9) +1
Next i
For i= 1 To 5
If i Mod2=0 Then
a(i) = a(i)\i
Else
a(i)= a(i) Mod i
End If
Next i
执行该程序段后,在下列选项中a(1)至a(5)各元素可能是( )
①每次将第i个数据和第2*i以及第2*i+1个位置的数据进行比较,将较大值交换到第i个位置上;
②从数组的第i(未排序数据个数一半位置)个位置重复步骤①一直比较到最前面,这样就可以将最大值交换到第1个位置;
③最终将1号位置上的值与未排序数据的最后一个进行交换,得到最大值;
④反复执行①②③三个步骤就可以将数据按升序排序;
过程如下图所示,其中a(1)=11,a(2)=25,a(3)=52,a(4)=39,a(5)=46,开始比较的位置从i=k\2个位置开始:
第一次排序过程:
步骤①:
步骤②:
步骤③:
第二次排序过程:
现要求在文本框Text1中输入一个整数k,对k个随机生成的两位奇数按上述排序方法进行排序,代码和程序运行界面如下所示,请在划线处填入合适的代码,并且在加框处代码有错误,请改正:
Dim a(1 To 100) As Integer
Dim k As Integer
Private Sub Command1_Click()
Dim i As Integer
k = Val(Text1.Text)
Randomize
For i = 1 To k
a(i) = ①
List1.AddItem Str(a(i))
Next i
End Sub
Private Sub Command2_Click()
Dim i As Integer, j As Integer, t As Integer, flag As Integer
For i = 1 To k - 1
For j =
To 1 Step -1
If Not judge(i, j) Then
If ② Then
t = a(j): a(j) = a(2 * j): a(2 * j) = t
Else
t = a(j): a(j) = a(2 * j + 1): a(2 * j + 1) = t
End If
End If
Next j
t = a(1): a(1) = a(k - i + 1): a(k - i + 1) = t
Next i
For i = 1 To k
List2.AddItem Str(a(i))
Next i
End Sub
Function judge(t As Integer, s As Integer) As Boolean
③
If a(s) > a(2 * s) And a(s) > a(2 * s + 1) Or a(s) > a(2 * s) And 2 * s > k - t Then
judge = True
End If
End Function
根据以上代码回答问题:
① ② ③

Private Sub Command1_ Click( )
Dim a(0 To 4) As Integer, b(1 To 4) As Integer
Dim key As String, s As String, n As Integer, k As Integer, i As Integer, j As Integer, sum As Integer
key="ABCDEFGHJKIMNC)PQRSTUVWXYZabdefghijklmnopqrstuvwxyz0123456789! @# $ %&.*"
Randomize
n= Val(Text1.Text)
a(0)=0:a(1)=26 :a(2)=52 :a(3)=62:a(4)=70 '记录每种符号的结束位置
s= ""
For i=1 To 4
b(i) =0 'b数组记录某类符号是否使用
Next i
sum=4 '当前未使用字符类型,初始为4种
Do While Len(s)+sum< n
k= '随机选择一个密码序号
s=s+ Mid(key, k, 1)
i= 1
Do While ![]()
i=i+ 1
Loop
b(i)= 1
sum=4-b(1)-b(2)-b(3)-b(4)
Loop
'生成剩余未出现元素密码,保证4种符号均有出现
For i=1 To sum
j=Int(Rnd*4)十1
Do While ( )
j=j Mod 4+1
Loop
b(j)=1
k=Int(Rnd * (a(j)-a(j- 1)))+a(j-1)+1
s=s+Mid(key, k, 1)
Next i
Text2.Text=s
End Sub
根据上述加密算法编写解密程序。程序在启动时读取密钥矩阵存入数组a 中,在文本框Text1
中输入密文,点击“解密”按钮,在文本框Text2 中显示明文。运行界面如图c 所示。
Const n = 3
Dim a(1 To n * n) As Integer
Private Sub Command1_Click()
Dim mw(1 To 2*n*n) As Integer
'存储密文数据,奇数位存储加密值,偶数位存储该数据在原文中的位置
Dim yw(1 To n*n) As Integer '存储解密数据
Dim k As Integer
'生成规模为n*n 的密钥矩阵存入数组a中,代码略
For i = 1 To Len(Text1.Text)
c = Mid(Text1.Text, i, 1)
If c <> "," Then
t = t * 10 + Val(c)
Else
mw(k) = Val(t): t = 0
End If
Next i
For i = 1 To k\2 '对密文解密,结果存数组yw
yw(mw(2 * i)) =
Next i
s = ""
For i = 1 To k\2
s = s + Chr((yw(i)) + 64)
Next i
Text2.Text = s
End Sub
Function getmm(x As Integer, n As Integer)
col = (x - 1) Mod n + 1
row = (x - 1) \ n + 1
getmm = a((col - 1) * n + row)
If row Mod 2 = 0 Then getmm =
End Function
a=input(“请输入a的值:”)
print(a*3)
假如从键盘输入5,则运行结果为( )
s1 = "2019GaoKao"
For i = 1 To Len(s1)
ch = Mid(s1, i, 1)
If ch >= "0" And ch <= "9" Then
ch = Str((Val(ch)+1) Mod 10)
s2 = ch + s2
ElseIf ch >= "a" And ch <= "z" Then
ch = Chr(Asc(ch) - 32) s2 = s2 + ch
End If
Next i
该程序运行后,s2的值是( )
micro:bit代码:
from microbit import *
while True:
if pin0.read_ analog()< 100:
pin2.write digital(0)
else:
pin2.write digital(1)
sleep(2000)
pin2.write_digital(0)
sleep(10000)
请分析该装置,完成下列题目。

编写一个VB程序实现如下功能:单击“开始循迹”按钮Command1,呈现10*10矩阵地图,并随机生成4个循迹点,分别用数字1表示,数字0表示非循迹点;计算4点中相距最远的两点的直线距离,显示在标签Label1中。程序运行界面如图b所示。

Const n = 10
Const m=4
Dim b(1 To 8) As Integer
Private Sub Command1_Click()
Dim f(1 To n* n) As Integer
Dim i As Integer, j As Integer
Dim w As Integer, k As Integer
Dim length As Single, maxlen As Single
Dim s As String
'生成矩阵地图和随机生成4个循迹点,0表示非循迹点,1表示循迹点,存于数组f中,代码略。
For i= 1 To n^2 '显示矩阵地图和4个循迹点
s = s+ Str(f(i))
If i Mod n=0 Then
List1. AddItem s
s=" "
End If
Next i
w=1
For i=1 To n
For j=1 To n
k = (n+1)* ((i-1) Mod 2)+(-1)-(i-1) * j
If Then '记录循迹点所在位置
b(2*w-1)=i
b(2*w)=k
w=w+1
End If
Next j
Next i
i=1
maxlen = 0
Do While i<=m-1
For j=i+1 To m
If length > maxlen Then maxlen = length
Next j
i= i+1
Loop
Label1. Caption = Str( maxlen)
End Sub
Function reck(x As Integer, y As Integer) As Single
Dim c As Integer, d As Integer
Dim h As Single
c=
d=Abs(b(2*x)-b(2*y))
h=Sqr(c^2+d^2)
reck = h
End Function