题目

y=在点A(1,1)处的切线方程是(　　)A.x+y-2=0                           B.x-y+2=0C.x+y+2=0                          D.x-y-2=0 答案：解析:y′=-,∴y′|x=1=-1.∴切线方程为y-1=-1·(x-1),即x+y-2=0.答案:A

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