题目

设0＜x＜1,a,b为正常数,则的最小值为(    )A.(a-b)2                                           B.(a+b)2C.a2+b2                                           D.a2-b2 答案：解析: +a2+b2≥+a2+b2=2ab+a2+b2=(a+b)2.取“=”时a2=b2∈(0,1).答案:B

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