题目

设NA表示阿伏加德罗常数，下列说法正确的是（  ）         A．标准状况下，22.4LCH4和CH2Cl2的混合物所含有的分子数目为NAB．3g的甲基中含有的电子数为1.6NA                                                                                                                                                                                                                                                                                                                                                                                                                                                                                                   C．0.5mol的有机物C15H32中含有的共键数为24NAD．现有乙烯、丙烯、丁烯的混合气体共14g，其原子数为3NA  答案：D解析:略 

查看本题答案和解析