题目
已知数集A={a2,a+1,-3}与数集B={a-3,2a-1,a2+1},若A∩B={-3},求A∪B.
答案:解:A∩B={-3},∴-3∈B.∵a2+1>0,∴集合B中等于-3的元素只有a-3或2a-1两种情形.(1)当a-3=-3,即a=0时,A={0,1,-3},B={-3,-1,1}.这时A∩B={-3,1},与已知A∩B={-3}矛盾,故舍去a=0;(2)当2a-1=-3,即a=-1时,A={1,0,-3},B={-4,-3,2},符合要求.因此A∪B={-4,-3,0,1,2}.