题目

已知数列{an}满足:an+12=an2+4,且a1=1,an＞0,求an. 答案：解:根据已知条件an+12=an2+4,即an+12-an2=4.∴数列{an2}是公差为4的等差数列,an2=a12+(n-1)·4=4n-3.∵an＞0,∴an=.

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