题目

  如图，已知CD∥AB，OE平分∠BOD，OE⊥OF，∠CDO=62°，求∠DOF的度数．  答案：解析:解：∵ CD∥AB      ∴ ··············· 1分∵                  ∴ ················· 3分∵ OE平分∠BOD              ∴············· 5分∵ OE⊥OF                   ∴·················· 6分∴ 8分要求∠DOF的度数，结合已知条件，只需求得∠DOE的度数．显然根据平行线的性质以及角平分线的定义就可求解 

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