题目

f(x)是以5为周期的奇函数,f(-3)=4,且cosα=,则f(4cos2α)=____________. 答案：解析:f(4cos2α)=f［4(2cos2α-1)］=f［4×2×()2-4］=f(-2)=f(-5+3)=f(3)=-f(-3)=-4.答案:-4

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