题目

方程3x2=x的解为　　．                                                                          答案：　x1=0，x2=　．                                                                              【考点】解一元二次方程-因式分解法．                                                   【分析】可先移项，然后运用因式分解法求解．                                              【解答】解：原方程可化为：3x2﹣x=0，                                                 x（3x﹣1）=0，                                                                                  x=0或3x﹣1=0，                                                                                解得：x1=0，x2=．                                                                          【点评】本题考查了解一元二次方程的方法，当把方程通过移项把等式的右边化为0后方程的左边能因式分解时，一般情况下是把左边的式子因式分解，再利用积为0的特点解出方程的根．因式分解法是解一元二次方程的一种简便方法，要会灵活运用．                                                                                            

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