题目

化学反应N2＋3H2＝2NH3的能量变化如图所示，该反应的热化学方程式是 A、N2(g)＋H2((g)＝NH3(g)；ΔH＝(a＋b) kJ·mol－1 B、N2(g)＋3H2(g)＝2NH3(g)；ΔH＝2(b－a) kJ·mol－1 C、N2(g)＋H2(g)＝NH3(l)；ΔH＝(b＋c－a) kJ·mol－1 D、N2(g)＋3H2(g)＝2NH3(l)；ΔH＝2(a－b－c) kJ·mol－1 答案：D

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