题目

函数y=f(x)的图象如图1-6-8所示,则y=f(x)的解析式为(    )图1-6-8A.y=sin2x-2                               B.y=2cos3x-1C.y=sin(2x-)-1                         D.y=1-sin(2x-) 答案：解析:A==1,b==1,.∴T=π,ω===2.∴y=sin(2x+φ)+1,x=,2x+φ=-π.∴φ=-π-.∴y=sin(2x-π-)+1=-sin(π-2x+)+1=sin(-2x+)+1=-sin(2x-)+1.答案:D

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