题目

12.已知,则( 的值等于                           . 答案:-256 解析:(1-x)5=a0+a1x+a2x2+a3x3+a4x4+a5x5.令x=1,则有a0+a1+a2+a3+a4+a5=0,即(a0+a2+a4)+(a1+a3+a5)=0;                                                                                     ①令x=-1,则有a0-a1+a2-a3+a4-a5=25,即(a0+a2+a4)-(a1+a3+a5)=25.                                                                                   ②联立①②有∴(a0+a2+a4)(a1+a3+a5)=-28=-256.
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